Problem in assigning value to a variable in shell script.
 

Hi,

Why doesn't "var1=`echo $var2 | grep pattern`" work ?
Please help me.

It should. What does the command in between tickers (`) return? What ***exact*** line are you using in your script? I need to see it exactly as-is, to the last quote and punctuation character, please, copy/paste directly. Also, explain ***how*** it doesn't work. Is there an error? Is it just empty? How are you retrieving or using $var1? What's the contents of $var2?

It does normally work. Can you copy and paste testing it at the command prompt, including an echo "'$var2'" before the problem variable assignment so we can see exactly what you are doing?

Thnks for the reply and sorry for the delay. The exact code is:

procinfo=`awk -F\\\t '/model name/{print $2}' /proc/cpuinfo`
varDual=`echo $procinfo | grep Duo`

Thnks for the reply and sorry for the delay. The exact code is:

procinfo=`awk -F\\\t '/model name/{print $2}' /proc/cpuinfo`
varDual=`echo $procinfo | grep Duo`

What is the output of awk -F\\\t '/model name/{print $2}' /proc/cpuinfo on your system?

Thanks for the replies. I get ": Intel(R) Core(TM)2 Duo CPU E8500 @ 3.16GHz".

So then what do you get after running:
My guess is it should be the same as:

Looks like the issue earlier I was getting is not appearing now. Thanks for all the replies it really helped.