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Old 05-06-2014, 01:15 PM   #1
mightyh
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print value from offset row with bash


I have a command that provides system config info for each volume. I am trying to query a file containing the information for each volume, search out a volume group and respond with the associated volume. So basically

if the associated volume group = x then print volume name.

Code:
Volume name:                   2

Volume status:                 Optimal
Thin provisioned:              

Capacity:                      ##### GB
Volume world-wide identifier:  
Subsystem ID (SSID):          
Associated volume group:       4
RAID level:                    

LUN:                           
Accessible By:                 

Drive media type:              
Drive interface type:          
Tray loss protection:          

Secure:                        

Data Assurance (DA) enabled:   

Preferred owner:               
Current owner:                 



Volume name:                   5

Volume status:                 Optimal
Thin provisioned:              

Capacity:                      ##### GB
Volume world-wide identifier:  
Subsystem ID (SSID):          
Associated volume group:       5
RAID level:                    

LUN:                           
Accessible By:                 

Drive media type:              
Drive interface type:          
Tray loss protection:          

Secure:                        

Data Assurance (DA) enabled:   

Preferred owner:               
Current owner:

Last edited by mightyh; 05-06-2014 at 04:03 PM.
 
Old 05-06-2014, 02:51 PM   #2
grail
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Sounds like a great idea ... so what have you done to solve the problem? Also, is the data shown the answer or what we are to start with?

Please also place code / data in [code][/code] tags to make it more readable.
 
Old 05-06-2014, 04:14 PM   #3
mightyh
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That is a sample of the data that i am trying to parse. I will turn the solution into a variable "$volumename" for another function.

I have a basic understanding of awk so i can definitely find the line with associated volume group but i am at a loss on how to print the volume name from 8 rows up.

This will find the line with volumegroup 1 and print it. But what i need is to print the volume name.
Code:
volumegroup = 1
awk -v volumegroup=$volumegroup -F":" '$1 ~ /volume group/ && $2 ~ volumegroup {print}'
 
Old 05-07-2014, 08:29 AM   #4
grail
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So why not store the volume name as you come across them and then when your expressions are correct you can print the saved value
 
Old 05-08-2014, 06:36 PM   #5
mightyh
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I would be grateful if you would show me how to do that, or point me to an existing thread.
 
Old 05-09-2014, 03:51 AM   #6
grail
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Same idea as what you have already done, simply add something like the following to the start:
Code:
$1 = "Volume name"{vname = $2}
To get just the name, seeing as there is a good deal of white space everywhere, I would add this to your separator so it is absorbed:
Code:
-F": *"
If there are tabs in there as well you will need to alter to suit
 
  


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