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Old 09-22-2011, 04:53 AM   #1
ghpradeep
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Registered: Mar 2011
Posts: 32

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PHP Warning: mysql_fetch_row() errror in global address book script.


Hi. I have installed qmail server on redhat. while configuration on global address book with below link:

http://wiki.qmailtoaster.com/index.p...l_Address_Book.

I am getting below error while running sqweb_gabook.sh script.
------------------------------------------------------------------------------------------------------
#Squirrelmail global address book updater...
PHP Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in /etc/qmailfile/sqweb_gabook.php on line 45
Global Address for hometest.com is available at /etc/qmailfile/hometest.com_gabook
Enter the fullpath using Squirrelmail config utility
select 6. Address Books option and configure address book in 3. Global file address book
More info: http://www.squirrelmail.org/docs/adm...n-7.html#ss7.5
-----------------------------------------------------------------------------------

I have pasted sqweb_gabook.php script below:

$domainname="****";
// your domain table name inside vpopmail database
$tablename="***";
$username="****";
$password="******";
$database="****";
$hostname="localhost";
$filename=$domainname."_gabook";
$global_abook="/etc/qmailfile/".$filename;

// process
$handle = fopen($global_abook, 'a');
$conn = mysql_connect($hostname, $username, $password) or die ('Error
connecting to mysql');
mysql_select_db($database);

$query = "select pw_name,pw_gecos from $tablename";
$result = mysql_query($query);

while(list($email,$name) = mysql_fetch_row($result))
{

$data=$email."|".$name."||".$email."@".$domainname."|\n";
fwrite($handle, $data);
}
mysql_close($conn);
fclose($handle);

?>
.

All username and password of mysql are working fine.

Please let me know that changes need to be done.

Br,
pradeep
 
Old 09-22-2011, 07:36 AM   #2
resolv_25
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Registered: Aug 2011
Location: Croatia
Distribution: Debian 10/Ubuntu 20.04
Posts: 64

Rep: Reputation: 15
I think this question shall be on some PHP forum, or programming forum here.

Anyway, such an error is typical either for a unsuccessful connection with a database or a wrong query.
At first glance, this line is wrong:
mysql_select_db($database);

it shall be:
Code:
mysql_select_db($conn, $database);
Also, if you wrap code, everything would be more readable. (on toolbar you have sign # or another one for PHP code).
 
  


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