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Old 12-06-2012, 03:20 PM   #1
andreqb
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Registered: Dec 2012
Posts: 1

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Pass file like list of params to find command


Hi everybody,

I have a list of ids and I need to find all files that contains this ids, the ideia is delete all this files.

This command returns me all files but in the same line:

find . -type f -print0 | fgrep -zFf temp

ps: temp is a file with all ids.

How can I find all files that contains all these ids?

thanksss

Last edited by andreqb; 12-06-2012 at 03:25 PM.
 
Old 12-06-2012, 04:11 PM   #2
hda7
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Registered: May 2009
Distribution: Debian wheezy
Posts: 251

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Quote:
Originally Posted by andreqb View Post
Hi everybody,

I have a list of ids and I need to find all files that contains this ids
By contain I assume you mean that the id is in the contents of the file; you seem to be checking for the id in the file name. If you mean to search for the ids in the contents of the files, try the following:
Code:
find . -type f -execdir fgrep -lf temp '{}' ';'
This will, for every file in the directory, call
Code:
fgrep -lf temp <filename>
The -l says to print out the name of the file if, and only if, it matches one of the patterns in temp; no other output is generated.

As a side note, "fgrep" is the same as "grep -F", rendering a second -F unnecessary.

Last edited by hda7; 12-06-2012 at 04:13 PM.
 
  


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