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Fond_of_Opensource

11-07-2006 12:18 AM

omitting space in shell script

HI friends,

I want to find the number of files in a given directory

ls -1 directoryname | wc -l

It gives the number of files in the given directory. But I want to store the number of files given as output of this command in a shell variable and autoincrement it.

Please help.
Thanks in advance...

Tinkster

11-07-2006 02:21 AM

I think I understand the "store in shell variable" bit, but on the auto-
increment you lost me ... what are you trying to achieve?

export LS_NUM=` ls -1 directoryname | wc -l`

Cheers.
Tink

Oliv'

11-07-2006 12:40 PM

Hi,

I think that auto-increment is maybe to count for example the number of files which are under /var. So he may want to do a loop and auto-increment its variable.
in that case you can do:
LS_NUM+=$(($LS_NUM+` ls -1 directoryname | wc -l`))
or
LS_NUM=`expr $LS_NUM + ` ls -1 directoryname | wc -l``

Oliv'

matthewg42

11-07-2006 12:47 PM

Note: the execute and put the results here syntax with the `back-ticks` can also be achieved using $(dollar-braces), e.g.

Code:

echo "The number of files is $(ls |wc -l)"

This has the advantage of being nestable. The example above with nested back-ticks fails because the shell can't work out if it's nested executions, or two next to one another.

When you say "auto-increment" what do you mean? I read that as wanting:

Code:

LS_NUM=$(ls |wc -l)

let LS_NUM+=1

Is that what you wanted?

Quigi

11-07-2006 02:44 PM

What does this have to do with omitting space?

Fond_of_Opensource

11-08-2006 01:19 AM

hi,

I want to treat it as an integer in for loop in shell script.

my.dying.bride

11-08-2006 03:03 AM

Quote:

Originally Posted by Quigi

What does this have to do with omitting space?

......lol :)

matthewg42

11-08-2006 04:08 AM

Quote:

Originally Posted by Fond_of_Opensource

I want to treat it as an integer in for loop in shell script.

You don't give a lot away do you? Do you mean this?

Code:

LS_NUM=$(ls |wc -l)

for (( i=$LS_NUM ; i>0; i-- )); do

    echo "$i binary files, getting piped into wall"

    echo "$i binary files, getting piped into wall"

    echo "and if one little file, gets bitrot and sent to /dev/null"

    echo "...there'll be $(($i - 1)) file(s) left"

    echo ""

done

OK, I'm a bum poet. It's hard to know what you want to do without more information. I hope this helps.

unSpawn

11-08-2006 07:02 AM

Yeah, post the script.

Fond_of_Opensource

11-09-2006 03:45 AM

thanks to all.

problem solved.....:)

archtoad6

11-18-2006 09:18 AM

Please post the solution, you got a lot help here & part of the culture of LQ is to post the solution for others to benefit from. Besides, several of your helpers are curious about the triggering problem.

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