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Old 12-07-2007, 04:34 AM   #1
bzlaskar
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Registered: May 2006
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not operator with grep


Greetings,

I want to display all lines from /etc/passwd file that does
not start with z.

How can I construct such a statement using grep.

grep -e ^z /etc/passwd

This command will display all lines starting with z.If
I add a not operator , my work will be done.

But I am not getting which null operator to use...

Please suggest me the correct grep command . With thanks in Advance.
 
Old 12-07-2007, 04:41 AM   #2
matthewg42
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The -v option inverts the output (i.e. outputs all input lines which do not match the pattern).
 
Old 12-07-2007, 04:46 AM   #3
bzlaskar
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Thanks Mathew for a quick reply.


Quote:
Originally Posted by matthewg42 View Post
The -v option inverts the output (i.e. outputs all input lines which do not match the pattern).
 
  


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