[SOLVED] Not able to extract last column from awk

vinaytp · 05-20-2011, 01:48 AM

Hi All,

I have a basic question of awk.

Code:

var=/test/build/create/sls
echo $var | awk '{ FS = ":" ; print $NF }'
/test/build/create/sls

I am trying to extract last column from the above awk one liner. I am not getting where am I getting wrong !!

Thanks,

EricTRA · 05-20-2011, 01:58 AM

Hello,

If you're trying to get sls as a value, at least that's what I understand from the above, then you need to set your field separator to / instead of : and also if I'm not mistaking take the FS declaration outside the {} like this:

Code:

echo $var | awk -F'/' '{ print $5 }'

if you want to get sls as value. If the value of $var is different and you always want the last column, then substitute $5 for $NF as in your first post.

Kind regards,

Eric

vinaytp · 05-20-2011, 02:08 AM

Many Thanks sir,

Actually while posting I made that mistake of putting ":" instead of '/' . I did not have a chance to copy/paste from terminal.

Thanks again !!

EricTRA · 05-20-2011, 02:09 AM

Hi,

You're welcome. If you consider your problem solved then please mark the thread as such. Have fun with Linux.

Kind regards,

Eric

grail · 05-20-2011, 04:27 AM

As long as we realise that awk is in no way needed for this task??

Code:

echo ${var##*/}