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Old 06-06-2012, 11:21 AM   #1
dsfreddie
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Registered: Jun 2012
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Move the files between Current day & a previous day


Hi All,

I have a requirement where I need to first capture the current day & move all the files from a particular directory between the current day & a previous day. (BUS_DATE)

Here is what I am trying, but it gives me errors. ( I think those are syntax errors)

Quote:
export BUS_DATE=`cat path/filename.txt| grep 'P_BUS_DATE' | cut -d"=" -f2`
CURR_DY=`date "+%Y%m%d"`
CURR_DY_SECS=`date --date=$CURR_DY +"%s"`
BUS_DATE_SECS=`date --date=$BUS_DATE +"%s"`
DAYS=`$((($CURR_DY_SECS - $BUS_DATE_SECS) / 86400 ))`
echo $DAYS
i=$DAYS
while [ $i -ge 0 ]
do
`mv /patha/filename.$(expr $CURR_DY - $i).dat /pathb/destination/`
i=$ [ expr $i - 1 ]
done
I am also attaching the errors I got,

Quote:
++ grep P_BUS_DATE
++ cut -d= -f2
+ export BUS_DATE=20120528
+ BUS_DATE=20120528
++ date +%Y%m%d
+ CURR_DY=20120605
++ date --date=20120605 +%s
+ CURR_DY_SECS=1338872400
++ date --date=20120528 +%s
+ BUS_DATE_SECS=1338181200
++ 8
script.ksh: line 31: 8: command not found
+ DAYS=
+ i=
+ '$DAYS'
scripts.ksh: line 33: $DAYS: command not found
+ '[' -ge 0 ']'
scripts.ksh: line 34: [: -ge: unary operator expected
Can you pls shed some light on this.

Thanks much in advance,
Freddie
 
Old 06-06-2012, 11:27 AM   #2
Snark1994
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You don't want the backticks in the DAYS= line:

Code:
DAYS=$((($CURR_DY_SECS - $BUS_DATE_SECS) / 86400 ))
Same goes for the 'mv' line:

Code:
mv /patha/filename.$(( $CURR_DY - $i)).dat /pathb/destination/
and the "i=" line at the bottom could be better written as:

Code:
i=$(($i - 1))
Hope this helps,

Last edited by Snark1994; 06-07-2012 at 07:40 AM.
 
Old 06-06-2012, 11:59 AM   #3
dsfreddie
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Registered: Jun 2012
Posts: 11

Original Poster
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Thanks Snark for your quick response :-)

I made the changes you mentioned. Here is the error I am getting,

Quote:
++ grep P_BUS_DATE
++ cut -d= -f2
+ export BUS_DATE=20120528
+ BUS_DATE=20120528
++ date +%Y%m%d
+ CURR_DY=20120606
++ date --date=20120606 +%s
+ CURR_DY_SECS=1338958800
++ date --date=20120528 +%s
+ BUS_DATE_SECS=1338181200
+ DAYS=9
+ i=9
+ [[ 9 -ge 0 ]]
++ expr 20120606 - 9
+ mv /path/filename.20120597.dat /iis_dev_data/wcc/cpmg/ctl/
mv: cannot stat `/path/filename.20120597.dat': No such file or directory
+ i=8
+ [[ 8 -ge 0 ]]
++ expr 20120606 - 8
+ mv //path/filename.20120598.dat /iis_dev_data/wcc/cpmg/ctl/
mv: cannot stat `/path/filename.20120598.dat': No such file or directory
+ i=7
+ [[ 7 -ge 0 ]]
++ expr 20120606 - 7
This error continues until loop is over.

Can you pls help
Freddie

Last edited by dsfreddie; 06-06-2012 at 12:26 PM.
 
Old 06-06-2012, 08:05 PM   #4
chrism01
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You're getting those because
Code:
++ expr 20120606 - 9
+ mv /path/filename.20120597.dat /iis_dev_data/wcc/cpmg/ctl/
(as far as bash is concerned) you are subtracting integers, NOT dates.
 
Old 06-07-2012, 07:43 AM   #5
Snark1994
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Like chrism01 said, if you wanted to work out the correct date, you could use 'date' again:

Code:
mv /patha/filename.$(date --date=@$(($CURR_DY_SECS - $i*24*60*60)) +%Y%m%d).dat /pathb/destination/
(I notice in your examples you use "date --date=123456789" not "date --date=@123456789". If your version of 'date' doesn't need the @, then just remove it from my code)

You're using date again, feeding it the current date in seconds, but subtracting $i*24*60*60 seconds (which should be $i days' worth of seconds) and then outputting the corresponding date.
 
Old 06-08-2012, 03:38 PM   #6
dsfreddie
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Registered: Jun 2012
Posts: 11

Original Poster
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Reading the dates from a file & moving the files from a directory

Hi All,

I am coding for a requirement where I need to read a file & get the values of SUB_DATE. Once the dates are found, i need to move the files based on these dates from one directory to another.

ie, this is how it will be in the file,

SUB_DATE = 20120608,20120607,20120606,20120606

Now, i need to move the file (with filename like a.20120608,a.20120607 etc) based on the above dates from /path/source to /path/destination.

Can anybody shed some light on how to achieve this in LINUX?

Thanks Much
Freddie
 
Old 06-09-2012, 06:43 AM   #7
David the H.
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Could you clarify it a bit more? What are the exact contents of the file? Is it just that line, or are there others? Please post a representative example.

And does each date in the SUB_DATE string match an exact filename? Could there be dates without files, or files without dates, and what should happen in such cases? Please post a sample of the directory tree as well.

In any case, this should all be doable with a simple shell script. A while+read loop, some simple string manipulation, and mv are probably all that's required. Here are some links to start you with:

http://mywiki.wooledge.org/BashGuide
http://mywiki.wooledge.org/BashFAQ/001
http://mywiki.wooledge.org/BashFAQ/100
 
1 members found this post helpful.
Old 06-09-2012, 07:03 AM   #8
pixellany
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Here's a start:

"filename" contains one date string---eg "20120908":

Code:
dat=`grep -o "20[0-9]*" filename`
cp filename filename_$dat
Note the "backtics"---not single quotes
 
Old 06-09-2012, 09:59 AM   #9
colucix
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@dsfreddie: moderator note: your new thread has been merged here, since the new question is strictly related to the previous one. Furthermore, keeping discussions in one place avoids confusion and gives your question a better exposure (in respect of members that already stepped in to help).
 
Old 06-10-2012, 11:52 AM   #10
Snark1994
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This is beginning to sound a little like an X-Y Problem... What is your actual end goal? What problem are you trying to solve?
 
  


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