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Old 11-25-2003, 06:45 PM   #1
leontini
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Registered: Aug 2003
Location: Melbourne, Australia
Distribution: Fedora Core 8-10
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Making charts in OpenOffice Calc


Hello all,
This is a fairly particular question, and one that I think the answer to will be fairly obvious to a more experienced user than myself, so please excuse my ignorance.
I have been inputing a bunch of data into excel spreadsheets, but I generate that data with some script that runs under Linux. I decided it would be easier to use OpenOffice Calc, but have run into this problem.

How do I create charts of data that is not in columns that are right next to each other? Excel lets me pick series after starting the chart wizard, does Calc have a similar option? I want to be able to mess with the ranges of data plotted, and which columns make up the x and y axes values.

Any help will be greatly appreciated, as this is really the last step I have to take in escaping the clutches of Microsoft.

Thanks,

Justin
 
Old 11-25-2003, 08:40 PM   #2
Tinkster
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That was a quite interesting undertaking :}

I managed, thanks to the brilliant help function ;)


What you do is, in the object bar on the left
hand side, long-click "insert object", then
select "chart".

Then you mark the area in the spreadsheet
where the chart is going to live.

Then, a dialog comes up for you to define the
range(s). You can either use the mouse, or
the keyboard to do so. I've made a quite trivial
example, two non-adjacent columns, which I selected
by $Sheet1.$A$1:$A$17;$Sheet1.$C$1:$C$17 ...


Eh voila, the rest is done by the wizard ;)


Cheers,
Tink
 
Old 11-25-2003, 10:42 PM   #3
leontini
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Registered: Aug 2003
Location: Melbourne, Australia
Distribution: Fedora Core 8-10
Posts: 61

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Tink,
You're a champ! I think I'm finally getting the hang of this. After bashing away at it myself, I found a similar solution to the one you presented.
Now, the next question is (not that this is really pressing). . . what if you want to make another column, other than the left-most one, the x-axis values? If you can solve that, the whole picture will be complete.

thanks,

Justin
 
  


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