ls command question
 

I'm writing a scripts that requires the names and dates of files within a directory.

I could do ls -l to get this information but it also has the owner and rights that I don't need. I thought I could pipe the ls command with a cut command to only get the date and the filename but I can't get it to work.

Does anyone have any suggestions? Thanks.

Have a closer look at awk ...

Cut, btw, should be just fine... what's the problem?


Cheers,
Tink

I don't know how to use cut. I assume its in the form

ls -l | cut.

but I don't know what options I need to pass to get the last two columns.

Heh ... have you tried a
man cut? :)


But really, since cut's delimiter handling is
a bit unwieldy I'd suggest using awk ...

try
ls -l | awk '{printf "%2d %3s %s\n", $7, $6, $9}'

Cheers,
Tink

thanks that makes worked. I tried using cut with the ' ' delimiter but it wasn't working well. awk is easier. J