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Old 12-10-2012, 06:37 PM   #1
iconig
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Registered: May 2012
Posts: 28

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lower triangular


Hi,
I was wondering if there is a way of using awk to extract the lower or upper triangular matrix from a symmetric matrix. Say I have this matrix:
$ cat data:
Code:
1 0 9 6 7 9
0 8 2 8 9 0
9 2 6 9 4 3
6 8 9 6 9 4
7 9 4 9 9 7
9 0 3 4 7 9
I am trying to do two things.
Result 1:
Code:
0 9 2 6 8 9 7 9 4 9 9 0 3 4 7
Result 2:
Code:
1 0 8 9 2 6 6 8 9 6 7 9 4 9 9 9 0 3 4 7 9
Result 1 has only the lower triangular without the diagonal while result 2 has the lower triangular and the diagonal.

Thanks.
 
Old 12-10-2012, 10:36 PM   #2
btmiller
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Registered: May 2004
Location: In the DC 'burbs
Distribution: Arch, Scientific Linux, Debian, Ubuntu
Posts: 4,284

Rep: Reputation: 371Reputation: 371Reputation: 371Reputation: 371
I haven't thought it out fully, but it would be a lot easier if you store the matrix row-wise instead of column wise. I've no doubt that this could be done with awk, but I'd probably use a small Perl or Python script to store it row-wise, e.g.:

Code:
#!/usr/bin/env python

import sys
n = 0
r = []

for line in sys.stdin:
    line = line.strip()
    larr = line.split()
    n += 1

    r.extend(larr[len(larr)-n:])

print r
Note that this is totally untested. Error checking and extending this code to not store the diagonal is left as an exercise to the reader. It should be fairly straightforward to transfer this to awk, for someone who knows awk syntax a bit better than I do :-).

Last edited by btmiller; 12-10-2012 at 10:38 PM. Reason: oops ... code typo...
 
  


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