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Old 11-25-2016, 10:45 AM   #1
freeroute
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List arrange on terminal


I have a big list like this (before the names there are empty spaces):

Nicolaes Tulp (15931674), physician, surgeon and mayor of Amsterdam
Gustav de Vries (18661934), mathematician
Hugo de Vries (18481937), geneticist

I would like to cut only names.
So the list should be:

Nicolaes Tulp
Gustav de Vries
Hugo de Vries


How could I do that?
I tried
Code:
tr -d ' \t' <inputfile>outputfile
But the result was:
NicolaesTulp
GustavdeVries
HugodeVries

Thank you in advance.
 
Old 11-25-2016, 11:04 AM   #2
rtmistler
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Hi,

How about trying:
Code:
 cut -d '(' -f1 <inputfile> > <outputfile>
What this does is "cuts" fields (-f) from the input file and puts them to stdout. You redirect to a file using the ">". -d specifies the delimiter, which in this case is the first parenthesis '(' and you wish only the first field prior to that delimiter.

Example:
Code:
$ cat 1.txt
Nicolaes Tulp (15931674), physician, surgeon and mayor of Amsterdam
Gustav de Vries (18661934), mathematician
Hugo de Vries (18481937), geneticist
$
$ cut -d ' ' -f1-2 1.txt
Nicolaes Tulp
Gustav de
Hugo de

Last edited by rtmistler; 11-25-2016 at 11:05 AM.
 
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Old 11-25-2016, 11:13 AM   #3
crazy-yiuf
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You can also use sed to match everything up to the parenthesis.
Code:
sed 's/\(^[a-zA-Z ]*\)(.*/\1/1' list.txt
 
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Old 11-25-2016, 11:14 AM   #4
freeroute
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@rtmistler
Thanks your advise. Working.
Almost good. I have 5 space characters before every name in my list and I would like to cut these, too. It is not shown my original post.
 
Old 11-25-2016, 11:27 AM   #5
crazy-yiuf
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Then you can do:
Code:
sed 's/^[ ]*\([a-zA-Z ]*\)(.*/\1/1' list.txt
Sed's a pain, but extremely useful. Especially if you're a programmer and need to refactor array[0][1] to getArray(0,1), or something like that.
 
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Old 11-25-2016, 01:00 PM   #6
rtmistler
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Quote:
Originally Posted by freeroute View Post
@rtmistler
Thanks your advise. Working.
Almost good. I have 5 space characters before every name in my list and I would like to cut these, too. It is not shown my original post.
Quote:
Originally Posted by crazy-yiuf View Post
Then you can do:
Code:
sed 's/^[ ]*\([a-zA-Z ]*\)(.*/\1/1' list.txt
Sed's a pain, but extremely useful. Especially if you're a programmer and need to refactor array[0][1] to getArray(0,1), or something like that.
crazy-yiuf has it correct; however in the event that you encounter a TAB as opposed to spaces, you may wish to include a search for TAB in the regex:
Code:
 sed 's/^[ \t]*\([a-zA-Z ]*\)(.*/\1/1' list.txt
 
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Old 11-25-2016, 01:24 PM   #7
pan64
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and you can do it in two steps, like:
Code:
sed 's/^[ \t]*//; s/[ \t]*(.*//'
the first one will remove the spaces before, the second one will remove ( and everything afterward. But remember it may not work properly if you have more than one (.
 
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