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ok, so really, even if a = "1234" and i try to test it against a known integer like (b=1235) and use "-lt", it'll work ok? hmmm..i'll try that.
thanks so much....for some reason i thought i had to convert it to the same type...im so used to other languages needing to know the type, i never would have thought that would work..
Yes. That's the way bash does it. It doesn't have any proper data type separation which can be a bit confusing at first. Some examples:
if [ "$A" -lt "$B" ]; then echo "$A is lesser than $B"; fi
if [ ! "$A" -lt "$B" ]; then echo "$A is not lesser than $B"; fi
if [ "$A" -ge "$B" ]; then echo "$A is greater than or equal to $B"; fi
if [ "$A" -eq "$B" ]; then echo "$A is equal to $B"; fi
if [ "$A" == "$B" ]; then echo "$A is equal to $B"; fi
if [ "$A" == "1024" ]; then echo "$A is equal to 1024"; fi
Last edited by i92guboj; 04-05-2009 at 05:01 PM.