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How to truncate mailq command output
Hello, as I hope all you're aware of output from "mailq" command.
For your information, it gives output in 3 rows, for example: ....... ........ 22713127A18 2798 Thu Sep 10 11:01:24 MAILER-DAEMON (connect to system.test.com[167.129.51.11]: Connection refused) appmgr@system.test.com 28B60127A19 2798 Thu Sep 10 11:11:29 MAILER-DAEMON (connect to system.test.com[167.129.51.11]: Connection refused) appmgr@system.test.com .... ...... ....... So now I just want to list out recipient adresses (which are in 3rd row of every column of the output), so how can I achieve that? Thanks in advance |
I can think of several ways; the simplest is to grep for @.
Slightly more complex but relying on structure rather than content: awk '{printf "%s\n",$3}' RS="\n\n" FS="\n" |
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