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Old 09-08-2008, 08:11 AM   #1
teguh.purnama
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Thumbs up How to take value from file (bash script)


The content of the file is (file name is varlist):

Quote:
list1: 235.214 -6532.211 0.00214
list2(addition): -6524.214 23.125 0.00234
how to take those value using bash script. I tried to use

Quote:
$var1=`cat varlist | grep "list1" | expr substr \([0-9]......)\`
it result only error.
 
Old 09-08-2008, 08:22 AM   #2
matthewg42
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  • Do not prefix a variable name with $ when assigning to it, only when taking the value.
  • Unnecessary use of cat, you can pass the input file name to grep directly as an argument.
  • You can use cut with -d option to split lines by some character, which might be cleaner than using expr.
 
Old 09-08-2008, 08:23 AM   #3
david1941
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var1 = `awk '/list1/{print $2}' varlist`

Dave

More clearly var1 = $(awk '/list1/{print $2}' varlist)

Last edited by david1941; 09-08-2008 at 08:24 AM.
 
Old 09-08-2008, 08:32 AM   #4
teguh.purnama
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awk script seems easier for me.
thanks for the answer.
 
  


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