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How to replace line with another line in shell script

Dear All,
I have the file abc.txt

cat abc.txt
This is a test file
Nothing is new in this world

I want to replace
"This is a test file" to "Text is replaced"

Code

Code:

FindString='This is a test file'

ReplaceString='Text is replaced'

Findarray=(`echo $FindString | tr ' ' ' '`)

ReplaceArray=(`echo $ReplaceString | tr ' ' ' '`)



# Length 

num_new_items=${#Findarray[@]};



# Length of replace array

ReplaceArrayLength=${#ReplaceArray[@]};



echo "Replace Array Length : $ReplaceArrayLength"



echo "Length $num_new_items";

for (( i=0;i<$ReplaceArrayLength;i++)); do

        sed  -i s/${Findarray[$i]}/${ReplaceArray[$i]}/g TestFile

#        echo ${array[$i]};

#        echo $i;

done

But this is not effective.
Any idea how to replace entire line either using sed or awk or any other utility.

Thanks in Advance,
Pramod

Hi,

how about:

Code:

sed 's/This is a test file/Text is replaced/' < abc.txt > abc.txt.new; mv abc.txt.new abc.txt

Evo2.

Thanks for the reply.
The changes are not reflected when i tried to run the following command.

export a="This is a test file"
export b="Text is replaced"
sed 's/$a/$b/' < abc.txt > abc.txt.new; mv -f abc.txt.new abc.txt

The problem is that you have $a and $b between single quotes, meaning they will not expand to their variables.
Use double quotes if you want to expand shell variables. Eg

Code:

a="This is a test file"

b="Text is replaced"

sed "s/$a/$b/"  < abc.txt > abc.txt.new; mv -f abc.txt.new abc.txt

Evo2.

It worked.. :-)

Thank you very much.

You can also use the -i option in place replacement

Code:

bash-3.1$ cat abc.txt

This is a test file

Nothing is new in this world

bash-3.1$ a="This is a test file";b="Text is replaced";sed -i "s/$a/$b/" abc.txt

bash-3.1$ cat abc.txt

Text is replaced

Nothing is new in this world