how to pass command-line parameter to shell script?
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$0 is the name of the command
$1 first parameter
$2 second parameter
$3 third parameter etc. etc
$# total number of parameters
$@ all the parameters will be listed
but in all honesy, you can go to shelldorado.com and get everything you want to know on sh, ksh, csh, bash, javascript etc. Great site with tutorials, examples, everything you will need.
xombboxer: I provided you with the solution.
By the way, in the future don't highjack other people's threads (especially 3-year old ones). Create your own thread instead.
Given that your shell.sh script looks like you posted above, you can execute it (ans pass the values to the variables) by typing what I suggested. The values will be passed to the script and echo will display the passed values. Is that what you wanted?
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