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Old 05-08-2012, 03:45 PM   #1
Leisurely Gentlemen
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Registered: May 2012
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How to grep sections of a line out and copy to new file


I have to grep out only parts of the lines and put into a new file

Lines look like this ie exampleA,exampleB,exampleC,exampleD

Now I only want exampleA,exampleB in my new file. How can I only select the first 2?

I hope this was clear enough. Thanks!

LG
 
Old 05-08-2012, 03:57 PM   #2
Nermal
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Code:
awk -F',' '{print $1","$2}' file_name
If you need to search then see this thread: http://www.linuxquestions.org/questi...ecords-942033/
 
Old 05-08-2012, 04:39 PM   #3
Leisurely Gentlemen
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Thank you.. Can you show me how to move it into a new file after this awk -F',' '{print $1","$2}' file_name
 
Old 05-08-2012, 04:43 PM   #4
David the H.
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Read the section in the bash guide on input/output for how to do file redirections.

http://mywiki.wooledge.org/BashGuide

Then go back to the beginning and read the whole thing.

And actually, cut would be more efficient for a simple job like this.

Code:
cut -d ',' -f 1-2 file > newfile
 
Old 05-08-2012, 04:44 PM   #5
Leisurely Gentlemen
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Quote:
Originally Posted by David the H. View Post
Read the section in the bash guide on input/output for how to do file redirections.

http://mywiki.wooledge.org/BashGuide

Then go back to the beginning and read the whole thing.

And actually, cut would be more efficient for a simple job like this.

Code:
cut -d ',' -f 1-2 file > newfile
Thank you sir!
 
  


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