LinuxQuestions.org - how to find the scope/definitions of a class/methods ?

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- - how to find the scope/definitions of a class/methods ? (https://www.linuxquestions.org/questions/linux-newbie-8/how-to-find-the-scope-definitions-of-a-class-methods-788836/)

how to find the scope/definitions of a class/methods ?

In Windows environment when I used Borlan for C/C++ compilation, I was used to find the the scope/definitions of the methods/classes by pressing

Code:

ctrl + F1

when the cursor was hovering on that method/class. How can I find the scopes/definitions in the GNU/Linux?

Code:

//atoi.cc

#include <iostream>



main(int argc, char* argv[]) {

float var_float = atof(argv[0]);

int var_int = atoi(argv[1]);

printf("var_float is %2.1f\nvar_int is %d\n",var_float,var_int);

}

Code:

[mq15@localhost c-c++_files]$ c++ atoi.cc -o atoi

atoi.cc: In function ‘int main(int, char**)’:

atoi.cc:7: error: ‘atof’ was not declared in this scope

atoi.cc:8: error: ‘atoi’ was not declared in this scope

Code:

[mq15@localhost c-c++_files]$ c++ --version

c++ (GCC) 4.3.0 20080428 (Red Hat 4.3.0-8)

Copyright (C) 2008 Free Software Foundation, Inc.

This is free software; see the source for copying conditions.  There is NO

warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

Best Regards

Code:

$ man atof

$ man atoi

two more confusions

Thanks.

1.1 If man shows manual of bash commands/utilities, how it is showing the manual of a c/c++ method i.e. atof()?
1.2 If atof() is not a c/c++ method, but it is a bash command/utility, then how we can use a bash command/utility i.e. atof() in a .cpp source file?

2. I have included stdlib.h and atoi.cpp is compiled with no errors, yet the result is not what I expect:

Code:

[mq15@localhost c-c++_files]$ ./atoi 5.4 6

var_float is 0.0

var_int is 5

What I expect is:

Code:

[mq15@localhost c-c++_files]$ ./atoi 5.4 6

var_float is 5.4

var_int is 5

See the cource code of atoi in post#1
Best Regards

1.1: Magic

1.2: atof is neither a c/c++ class/method nor a bash command/utility

2.0: Of course the result is not what you expect. This is a consequence of the fact that you do not know what argv[0] is supposed to be.

P.S.: Conduct the following experiment: write a C program which prints argv[i] (0 <= i < argc) on separate lines.

1.1 Still not satisfied :(
1.2 Then what atof actually is ?
2.0 Got it now. argv[0] holds the string the file was invoked with, in the terminal.
argv[1], argv[2]...argv[i] are supposed to be string values.

Code:

//arguments.cc

#include <iostream>

#include <stdlib.h>



main(int argc, char* argv[]) {



for(int i=0; i< argc; i++)

        printf("arg[%d] = %s\n",i,argv[i]);

}

Code:

[mq15@localhost c-c++_files]$ ./arguments str 5 6.7

arg[0] = ./arguments

arg[1] = str

arg[2] = 5

arg[3] = 6.7

The main problem is still unsolved: How to find the scope/definition of c++ classes/methods???
For example if I use

Code:

cout<<"Hello World";

, I get

Code:

‘cout’ was not declared in this scope

and doing man cout shows No manual entry for cout

Put this before the main funciton in your c++ code. You'll be able to compile the C++ code

using namespace std;