how to extract from a string
 

Hi,

I have a string "ip=ip_address 172.16.0.17", how can i extract 172.16.0.17 from it???

Regards,

Owais

Hi,

this should do the job:

echo "ip=ip_address 172.16.0.17" | grep -wo "[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*"

Regards
dmdeb

clunky I know but
cat source_file | sed {s/"ip=ip_address "//} | sed {s/'"'//g}

alright here is another way too
awk {'print $2'} sourcefile | sed {s/'"'//g}

It's important to focus on the rule to be followed----in this case, you might be wanting several different things:
---that exact IP address
---ANY legal IP address
---Anything following the word "ip_address"

If it helps, here's an excerpt from another thread---with a Regex that matches any legal IP:

I am not sure if 'ip' is a variable and so we work with that or if the whole string is being used. I will assume the latter as the solution is easily adaptable to 'ip':

Assuming the simple case

i want extracted data to be stored into another variable

Hi,

In the following, the output of "some command" will be stored in the variable y.
Evo2.

i'm using the following command :

echo "ip=$ip" | grep -wo "[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*"

this command extracts the data but i want to save it into another variable

Did you read the previous reply?

@grail

your solutions just prints the value 172.16.0.17, it doesn't insert in into another variable...

grail was referring to post #9.

That will not reliably extract IP addresses.....It will, for example match these strings:
...
451239798...
..567.