LinuxQuestions.org - [SOLVED] How to execute .sh file from different directory though a c++ Program

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How to execute .sh file from different directory though a c++ Program

Hello,

Sorry if this is not correct place for posting this but i was trying to write a short c++ code to choose different conky's.

Code:

switch(choice)

{

case 1:                system("killall -9 conky");

                system("conky -c ~/.conky_config_files/.conky_grey/conkyrc_grey");

                break;



case 2:                system("killall -9 conky");

                system("conky -c ~/.conkycolors/conkyrc");

                break;



case 3:                system("killall -9 conky");

                system("conky -c ~/.conky_config_files/.my_conkyrc/conkyrc");

                break;



case 4:                system("killall -9 conky");

                system("conky -c ~/.conky_config_files/.Conkydidi/conkyrc");

                break;



case 5:                system("killall -9 conky");

        //        execl("~/.conky_config_files/.GoldnGrey/conky.sh","conky.sh", NULL);

        //        system("chmod 777 ~/.conky_config_files/.GoldnGrey/conky.sh");

        //        system("bash ~/.conky_config_files/.GoldnGrey/conky.sh");        

                break;



default:        cout<<"\nAgain.\n";

                goto again;

}

My case 5 is not working, tried almost evrything on internet.
I dont know much bash coding. In this program i was trying to execute conky.sh from any directory.

Also, i want to hide the terminal on which i execute this program.

Any help?!!?!?

PS: i know case 5 is commented.

Why C++? Why not just use bash?

For closing the terminal, I'm pretty sure you can configure conky to jump to fork or run as a daemon or do some kind of magic so that it will not be a child process of your program, and so you can run 'xterm -e "your_program"' and the terminal will close after it's finished but conky won't... I think it's the "background yes" .conkyrc option, but can't remember offhand.

Finally, what commands are you trying to run in case 5? (i.e. if you were doing it manually, from a terminal, what commands would you want to enter?

Do you have a

Code:

#!/bin/bash

in the top of your script?

The OS needs to understand how to run the shell.

If not try:

Code:

/bin/bash <script to run> <command line parameters>

for execl to able to execute a script it requires #!/bin/bash as the first line.

I just wanted to create a simple gui to select from different conky configuration. Can i do that with bash coding?
And in case 5 i only tried to run script "~/.conky_config_files/.GoldnGrey/conky.sh" from different directory, say from Desktop!

Ah, if you're creating a GUI, then stick with C++. Have you checked it's a) executable (or run "chmod 755 <filename>", assuming you own the file) b) has the "#!/usr/bin/env bash" line at the start, as other people suggested? Then you should just need to have

Code:

system("~/.conky_config_files/.GoldnGrey/conky.sh");

to run it. Also, it may be worth putting some 'echo' code (or even use 'xmessage') in your conky.sh file, so you can check it runs - it is entirely possible that your C++ code is running the file correctly, but for some reason conky isn't starting, in which case the bug squashing needs to be done on that code, not your C++.

Snark
Thanks, As i was coding in cpp,adding "#!/usr/bin/env bash" didn't work nor in system(""). But making file executable before executing it, helps.
ie.

Code:

system("chmod +x ~/.conky_config_files/.GoldnGrey/conky.sh");

system("~/.conky_config_files/.GoldnGrey/conky.sh");

Above one works!!!

But how to hide that terminal???
i wish to hide terminal when execution of conkyrc is done..

Hm... Like I said, I'm pretty sure it's conky making that terminal. Look:

Code:

/* ~/test/test.cpp */

#include <cstdlib>

#include <gtk/gtk.h>



static void run_script(GtkWidget *widget, gpointer data){

        g_print("Running...\n");

        system("~/test/1file.bash");

        g_print("...and done.\n");

}



static gboolean delete_event(GtkWidget *widget, GdkEvent *event, gpointer data){

        g_print ("Exiting.\n");

        return FALSE;

}



static void destroy(GtkWidget *widget, gpointer data){

        gtk_main_quit ();

}



int main(int argc, char *argv[]){

        GtkWidget *window;

        GtkWidget *button;

        gtk_init (&argc, &argv);

        window = gtk_window_new (GTK_WINDOW_TOPLEVEL);

        g_signal_connect (window, "delete-event", G_CALLBACK (delete_event), NULL);

        g_signal_connect (window, "destroy", G_CALLBACK (destroy), NULL);

        gtk_container_set_border_width (GTK_CONTAINER (window), 10);

        button = gtk_button_new_with_label ("Run script!");

        g_signal_connect (button, "clicked", G_CALLBACK (run_script), NULL);

        gtk_container_add (GTK_CONTAINER (window), button);

        gtk_widget_show (button);

        gtk_widget_show (window);

        gtk_main ();

        return 0;

}

Code:

#!/usr/bin/env bash

# ~/test/1file.bash



echo Ran file 1

sleep 10

And:

Code:

$ ls -l 1file.bash

-rwxr-xr-x 1 snark users 46 Jul  4 10:41 1file.bash

$ gcc -Wall -g test.cpp -o test `pkg-config --cflags gtk+-2.0` `pkg-config --libs gtk+-2.0`

$ ./test

This doesn't open a terminal for me, just prints the output to the terminal already running. And if I run the script from my desktop, then no terminal opens. Can we see the contents of the script you're running? (also, you shouldn't need to run chmod every time - only once. So you can remove that line from your code)