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Old 07-06-2004, 11:13 PM   #1
BigCliff1951
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Registered: May 2004
Location: Dayton,Ohio
Distribution: Mandrake
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Question How many Gb's should I have for MDK 10.0?


[History] I had MDK 9.1 on my computer, but somehow I lost the download. ????...Don't know how I did that...
My old Compaq has only a 15 Gb hard-drive, and I need to know how much space I need to allocate to the MDK 10.0..(re: Dual-boot)...
I did load up the first cd-1 (in expert mode) to see what it had to tell me on what was out there..and this was the info:
hda1: 9,664 Mbytes,Type<Oxc> (Win98Fat32,Lba Mapped)
hda5: 4,658 Mbytes,Type<Oxc> (Win98Fat32,LBA Mapped)
/mnt/win-c ! /mnt/win_d hda 13Gb

Where's the other 2Gb's??? Hmmmm....
Where can I find info. on the correct mount points, and how much to allocate to them....

Sorry for being a REAL newbie to this...

 
Old 07-07-2004, 05:50 AM   #2
Vlad-A
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Registered: May 2004
Location: Vienna, Austria
Distribution: Open SuSE 11, Mac OS X 10.5
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The numbers are correct.

Storage Vendors are using base 10 for capacity and operating systems use base 2.

So, for storage vendors:
1 kByte=1000 (=10^3)Bytes, 1 MByte=1000 KByte, ...etc.
and for an operating system:
1 kByte=1024 (=2^10)Bytes, 1 MByte=1024 KBytes, ...etc.

15 GBytes for storage Vendors are
15*1000*1000*1000 Bytes

The System will see

15*1000*1000*1000/(1024*1024*1024) [Bytes] so about 13.98 GByte

That's also actually what you see:
hda1: 9,664 Mbytes,Type<Oxc> (Win98Fat32,Lba Mapped)
hda5: 4,658 Mbytes,Type<Oxc> (Win98Fat32,LBA Mapped)

9,664+4,658 = 14322 [MBytes] = 13.98 GByte

The Space you need depends on what packages you would like to install.
A full install will require about 3.5 GB. Plus about 250 MB Boot and 512 MB for swap.

If you do not install everything (e.g. only KDE or GNOME) 5.5 GB could be OK.

Last edited by Vlad-A; 07-07-2004 at 06:31 AM.
 
  


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