[SOLVED] How do i print names with status

VijayB · 07-18-2014, 12:30 AM

Hi,

I have a text file say test.txt. This test file has contents as :

Amit=2
Sahil=3
Vijay=1

i check the integer value in front of the names & print the status by following shell script:

#!/bin/bash
for i in $(cat ~/Precheck/test.txt | awk -F= '{print $2}')
do
if [ "$i" -eq 1 ]
then
echo " Guest has read access "
elif [ "$i" -eq 2 ]
then
echo " Guest has Read/Write access "
elif [ "$i" -eq 3 ]
then
echo " Guest has admin access "
else
echo "Guest does not have access"
fi
done

Output of this shell script is:

Guest has Read/Write access
Guest has admin access
Guest has read access

But the requirement is that instead of Guest , i should be able to print the names of the guests as well.

For example : Guest Amit has read/Write access & so on.

Can somebody please suggest how do i do that.

Thanks in Advance!

Vijay

TenTenths · 07-18-2014, 03:07 AM

Ok, so what have you tried so far?

grail · 07-18-2014, 07:39 AM

First of all, please place code or data inside [code][/code] tags so it is readable and legible.

Next I would suggest you look at how to read from a file using a while loop in bash and at the field separator IFS (also used in bash)

VijayB · 07-18-2014, 08:25 AM

@TenTenths : i tried cascaded for loop but it didn't work. Can you suggest something else?

TenTenths · 07-18-2014, 08:35 AM

Make use of awk and consider using case instead of if/elif.

I could easily give you an elegant solution if you want it, but that stops you learning about how to do stuff yourself.

For example, this is my output using your input file:

Code:

# ./level.sh test.txt
Amit has Read/Write access
Sahil has admin
Vijay has read access

VijayB · 07-19-2014, 02:40 AM

Hi TenTenths,

Thanks for boosting me up.

I am able to define just one variable & names i have defind inside case statement. can you please help me out , how can i map names with values.
The code that i am using is as follows:

Code:

#!/bin/bash


cat ~/Precheck/test.txt | awk -F= '{print $2}'| while read i ; do
	
case $i
in

1) 
Name=Vijay
echo -e "Guest $Name has read access" ;;

2)
Name=Amit
echo -e "Guest $Name has read/Write access" ;;

3)
Name=Sahil
echo -e "Guest $Name has admin access" ;;
 
esac
done

Thanks in Advance!

Vijay

TenTenths · 07-19-2014, 03:02 AM

Script level.sh

Code:

#!/bin/bash

for LINE in $(cat $1) ; do

  USER=$(echo ${LINE} | awk -F= {'print $1'})
  ACCESS=$(echo ${LINE} | awk -F= {'print $2'})

  case ${ACCESS} in

    1)
    echo "${USER} has read access"
    ;;

    2)
    echo "${USER} has Read/Write access"
    ;;

    3)
    echo "${USER} has admin"
    ;;

    *)
    echo "${USER} does not have access."
    ;;

  esac

done

Use: ./level.sh ~/Precheck/test.txt

grail · 07-19-2014, 10:25 AM

Code:

while IFS='=' read -r user access
do
    case "$access" in
      1) echo "$user has read access";;
      2) echo "$user has Read/Write access";;
      3) echo "$user has admin"
      *) echo "$user does not have access."
    esac
done<"$1"

Call it with:

Code:

./access.sh input_file