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Old 03-20-2007, 04:32 AM   #1
mr.v.
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Registered: Jun 2006
Distribution: Slackware 11
Posts: 56

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how do I display the user of a process using ps?


Hi all when I run
Code:
ps -A
I get a list of PIDs and names but not the user they belong to. the -u option seems to mention users and
Code:
ps -u
prints processes owned by my current user, but I'd like to display ALL users and
Code:
 ps -Au
gives me an error. I was wondering if this is possible? and if so, what's the syntax. The man page is entirely unhelpful.

Thanks for the help!
 
Old 03-20-2007, 04:40 AM   #2
mr.v.
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Registered: Jun 2006
Distribution: Slackware 11
Posts: 56

Original Poster
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uyyy never mind...i figured it out after some more trial/error
Code:
ps -A u
works
I guess you need a space and no dash in front of the lowercase 'u' to get it to work.
 
Old 03-20-2007, 11:29 AM   #3
binary_0011
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Registered: Apr 2006
Location: Singapore
Distribution: RHEL4,FC4,FC5
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does ps - aux works on slackware?
 
Old 03-20-2007, 02:40 PM   #4
mr.v.
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Registered: Jun 2006
Distribution: Slackware 11
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yeah it does...Thanks for the help!

it doesn't work with the space between the ps and the - but either
ps -aux
or
ps aux without the - work well. Apparently according to the ps man page ps -aux is not the same as ps aux. Apparently, ps -aux interprets that it should list the processes for user x instead of ps aux which should list processes for all users.

This is one part of linux I feel that I'll never understand. How to pass command line options. I get it when they're complete like --user=<something> --this-does-something-else --this-does-another

but when they're just single letters some programs let you do them without a - like tar and some require a - and the most frustrating is when (like ps) each letter means something different if the - is present or not.
 
  


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