how can i use sed to cut out all the text up until the pattern?

daweefolk · 02-15-2011, 09:02 AM

I want to cut out part of the 'uptime' output so all it displays is the load average. In the end I want to cut out everything before the word 'load'. I am a total sed newbie and could really use some examples or links. I've googled and haven't found anything useful yet.

##edit###
I used the 'cut' command- The code was

Code:

uptime |cut -d, -f 2,3,4,5 |cut 13-

szboardstretcher · 02-15-2011, 09:09 AM

Quote:

Originally Posted by daweefolk

I want to cut out part of the 'uptime' output so all it displays is the load average. In the end I want to cut out everything before the word 'load'. I am a total sed newbie and could really use some examples or links. I've googled and haven't found anything useful yet.

You could use cut..

Code:

uptime|cut -b33-

grail · 02-15-2011, 09:09 AM

Well the simplest version is probably:

Code:

uptime | sed s'/^.*load/load/'

druuna · 02-15-2011, 09:14 AM

Hi,

cat /proc/loadavg

EricTRA · 02-15-2011, 09:17 AM

Hi,

Or with awk, dirty but works

Code:

uptime |awk -F',  ' '{ print $3, $4, $5}'

Kind regards,

Eric