help with a shell script that runs 'dos2unix' command on files in a directory,

keerti · 01-30-2012, 08:28 AM

hi all,
i need a shell script that runs <dos2unix 'file1.sh' 'file2.sh'>
on all the files that are present in a directory. the files are not in any sequence , and they will be named in no order.

please help , as this is a tedious process in my work everyday. this script could help me save hours of manual work!

corp769 · 01-30-2012, 08:43 AM

Do you mean automatically? You can set up a script, and run it with cron. What have you come up with so far?

thund3rstruck · 01-30-2012, 08:55 AM

Something like:

Code:

find . -maxdepth 1 -type f | xargs -I "{}" dos2unix "{}"

Runs dos2unix against all the the files in the current working directory

grail · 01-30-2012, 09:04 AM

How about a simple loop and perform each task on the files found?

Cedrik · 01-30-2012, 09:53 AM

Why not just use shell globbing

Code:

dos2unix *.sh

suicidaleggroll · 01-30-2012, 10:05 AM

Or if dos2unix can only work on one file at a time:

Code:

for i in *.sh; do dos2unix "$i"; done

Cedrik · 01-30-2012, 10:06 AM

Why write shell script in dos env anyway