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Old 02-06-2013, 12:45 PM   #16
atjurhs
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Registered: Aug 2012
Posts: 183

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Quote:
Originally Posted by David the H. View Post
I think then that what you really want is something like this:


Code:
#!/bin/bash

topdir=${1:-defaultdir}
outfile=${2:-defaultfile}

awksearch(){
	awk -F ',' '$10 == 42 { count++ } END{ print FILENAME , count }' "$1"
}

cd "$topdir"

while IFS='' read -r -d '' fname ; do

	awksearch "$fname"

done < <( find ./ -type f -name "file*.txt" -print0 ) | sort -k2nr >"$outfile"

exit 0
I set it up so that you could override the default startdir and output file on the command line. It's only been slightly tested though, since I don't have the data you do.
Hi guys, I've been using David's scripty and it's works really great for what its supposed to do. Now I'd like to modify it a little....

I still need it to search down a bunch of directories, looking in file*.txt to find the number 42 in column 10, but for this next job when it finds 42 in column 10, I need it to print out what's in column 9

I guess where I'm having trouble in changing the script myself is understanding how the print statement is being used in David's script. I understand how to write a "basic" print statement. I think it's just that I don't understand how it's being used. Whenever I change things in it I get either a syntax error, path must exceed expression, or invalid predicate

thanks for whatever help you can, Tabby
 
  


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