Help me in Grep Command + cd command in single line
 

Can anyone help me in filtering the job name thru grep command.The command also should have cd.
for eg.,
pwd=/home/Jei
i want command like path=cd $pwd | grep 'jobname' O*

will the above command work

This doesn't really make sense.
path=cd $pwd
This will set the variable "path" to the string "cd" and then try to run a $pwd command which isn't a command.

And what do you mean by job name, and how is cd'ing to a directory going to print it out?

Without the pipe, "grep 'jobname' O*" will find lines of text in files starting with 'O' that have the word jobname in them.

Maybe you want:
DIR=/home/jei
cd ${DIR} ; grep 'jobname' O*

or

DIR=/home/jei
grep 'jobname' $DIR/O*

or simply

grep 'jobname' /home/jei/O*

If the directory isn't a constant, such as an argument to a script you might do something like:
dir=$1
cd ${dir} && grep 'jobname' "${dir}/O"*

Help in Grep Command
 

Thanks but there are few things that i need to explain i think.


#!/bin/sh
Home=/sample/docs/learn
Met_path=$Home/$1
job= cd ${Met_path}|`grep 'WM_EOH_HN' O* |cut -d : -f 1`
start_time= `head -6 $job | tail -1 |cut -d '' -f 1-3`
echo $start_time


This is the code that i go for. What i planned to do is i have job name that has the job name as 'WM_EOH_HN' and i am taking the name of the job and from that taking the starting time and printing it.

Jei;
I would advise you to try the various commands one at a time. Once you understand them, then you can put them together.

First, jschiwal already explained that this will not work:
job=cd $xyz
Try it yourself so that you understand why.

Next, you have this:
`grep ....|cut ....`
This make no sense. The backtics are used to pass the result of a command to something else. For example:
list=`ls -l` would list the current directory and assign the results to the variable "list". In you case, you do not use the value of the expression inside the backtics.