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Grouping commands in bash

Hi ALL,

I've question about grouping of commands in the bash.
For the sake of simplicity I'll show a bit artificial example but it explain the issue.
For example I can run following commands:

Code:

$ date; date

Wed Dec 12 11:52:46 EET 2012

Wed Dec 12 11:52:46 EET 2012

Excellent, but now I would like to run the same commands in different time zone:

Code:

$ TZ='Asia/Kolkata' date; date

Wed Dec 12 15:24:07 IST 2012

Wed Dec 12 11:54:07 EET 2012

Not perfect, the result is not exactly what I want. The first command executed in the specified timezone but the second one is executed in default system timezone. But I would like to run both commands in the specified timezone.
I know that bash allows grouping of executed commands like below:

Code:

$ (date; date)

Wed Dec 12 11:58:56 EET 2012

Wed Dec 12 11:58:56 EET 2012

Unfortunately in this syntax I can't specify timezone:

Code:

$ TZ='Asia/Kolkata' (date; date)

bash: syntax error near unexpected token `('

So, can anybody help me and show correct syntax of command line.

Thanks.

P.S. I know that I can export variable TZ to environment and then execute commands from the example, but I want to find out how to do that with help of a single command line :cool:

This ?

Code:

(export TZ='Asia/Kolkata' && date && date)

creates a subshell, so your parent shell retains orig TZ (if that's what you want)

Quote:

Originally Posted by chrism01 (Post 4847596)

This ?

Code:

(export TZ='Asia/Kolkata' && date && date)

creates a subshell, so your parent shell retains orig TZ (if that's what you want)

Hi chrism01,

Thank you very much. Your answer give me right direction to write what I want:

Code:

$ (TZ='Asia/Kolkata'; date; date)

Wed Dec 12 12:36:43 EET 2012

Wed Dec 12 12:36:43 EET 2012

Many thanks.