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Old 04-03-2008, 10:09 AM   #1
ihickman
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grep help


Hello -- I can't seem to find how to do this.

My grep command: grep ms filename outputs::

<snip>
1207169821905 DC 313ms RC:1000 RID:5 PID:405708 TIMES:289 0 1 0 0 3 0 16 2 0 0 2
1207170392173 DC 301ms RC:1000 RID:5 PID:270582 TIMES:265 0 0 1 0 3 0 23 5 0 0 4
1207170405346 DC 378ms RC:2005 RID:5 PID:376912 TIMES:371 0 0 0 0 3 1 3
<snip>

Question::

How do I narrow my query so it only shows the ###ms so it outputs::

313ms
301ms
378ms

Thanks in advance
 
Old 04-03-2008, 10:23 AM   #2
acid_kewpie
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*I* would do... "grep <etc> | cut -f 3"
 
Old 04-03-2008, 10:37 AM   #3
ihickman
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Hey Thanks for the direction Chris;

I needed to specify my 'delimiter' first. But your suggestion defiantly got me on track.

grep ms <file> | cut -d ' ' -f 3
 
Old 04-03-2008, 12:04 PM   #4
colucix
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Or something like
Code:
grep -o ...ms filename      # if exactly three digit numbers before ms
grep -o [1-9]*ms filename   # for numbers of any length
 
Old 04-03-2008, 12:09 PM   #5
acid_kewpie
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ahh, i always forget what the default field seperator is...
 
Old 04-03-2008, 02:42 PM   #6
prad77
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If the format is kind of same, then

awk { print $3 } filename

Gentoo

Last edited by prad77; 04-17-2008 at 04:39 AM.
 
  


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