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Old 06-27-2008, 03:02 PM   #1
b3nder
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Registered: Jun 2008
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grep command from bottom to top of a file.


Trying to figure something out that hopefully someone can shed some light on...

What I am trying to do is search a log file from the bottom to the up grabbing the last 10 instances on an ip (or string i specify)...

when using 'tail -xxxx /var/log/messages | grep x.x.x.x'.. this will only show results if it is in the range xxxx that I specify... which is Ok because i can keep increasing the xxxx range until i get enough results but that seems tedious and that there has to be an easier way to accomplish this..



anyone have any idea's? been searching Google for the past few hours and not finding anyway to work with grep to search from bottom up and stop when i get a certain number of hits.


Thanks!
 
Old 06-27-2008, 03:38 PM   #2
beadyallen
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Registered: Mar 2008
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Use 'tac' (cat backwards )
Code:
 tac your.log | grep stuff
I didn't know about it but found it on perl monks. You learn something new everyday.
 
Old 06-27-2008, 03:59 PM   #3
colucix
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Just exchange the commands:
Code:
grep x.x.x.x /var/log/messages | tail -10
 
Old 06-30-2008, 08:08 AM   #4
b3nder
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Registered: Jun 2008
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Thanks!

tac works perfect for the results that i want.

As for the "grep ' xxxx ' /var/log/messages | tail -10", it does return the correct results, the only problem that i found with using that is that it does end up having to search through the entire file and then it returns the last results.. takes a long time depending upon the size of the document.

appreciate the help as always!
 
  


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