I need some help on the following scenario:

There are some application names that i have placed in a text file called "print.txt", Need to check the process running or not for each application listed in the text file and should through an email in case of any of the application is down. I have written one sample script, could you please help me out to get the actual logic.


#!/bin/bash
#

apps=/opt/apache/qwest/websites
cd $apps
###### This will print list of all applications into one txt file######
ls > print.txt

for username in `awk -F: '{print $1}' /opt/apache/qwest/websites/print.txt`
do
echo "Username $((i++)) : $username"
pr=`ps -ef | grep $username|grep -v 'grep'|head -1|cut -d' ' -f6`
echo " $pr "
done

not sure why the field separator for awk is : ?
also why are you incrementing i; you dont see to be using it ?

i would use ls -1 to get a single-column list.

with the limited insite i have into your situation i think you just would need to run pgrep for each program.

the file print.txt contains the applications like :

abc-30101-40086
def-54361-54212
etc.....

And now from the above script in my earlier post produces the output as :

1 abc-30101-40086
5434 (PID for the first app)
2 def-54361-54212
6412 (PID for the second app)
etc......


Actually all these applications are hosted on single server, That is the reason i used the for loop to get the PID's of each application from the print.txt file, That's the case i ahve used the increment, Now i got stuck in how to write any loop either for or while, need to check the process of each and every line (applications) in the print.txt and send an email.


Hope that makes sense about my requirements.

still not following but if you need to email the output this should work:

@Saicharan Burle,

Is this you want ?

1 members found this post helpful.

Hi, Can you help me understanding the below command:

pgrep $app > /dev/null ;


Because, I have replaced your code with same thing like below: getting no process for all the applications

#!/bin/bash
#Script: test.sh

apps=/opt/apache/qwest/websites*

for file in $apps ; do
app=${file##*/}
if pgrep $app > /dev/null ; then
echo "$app: Process is running"
else
echo "$app: No such process"
fi
done

Output:

aa99036-eap-int1-30101-40086: No such process

Infact the process of all applications are running if i give ps -ef | grep "app"


Moreover i need the Loop functionality as well

pgrep $app > /dev/null ;
This blocks pgrep from displaying PID in terminal.


apps=/opt/apache/qwest/websites*

Replace this with:

apps=/opt/apache/qwest/websites/*

I am sorry I forgot to add the ? in the earlier post only, I have already changed in the script and executed but no luck yet,,

apps=/opt/apache/qwest/websites/*

run it like this and show us the output in #code tags:

Can you show what is in '/opt/apache/qwest/websites'

And also, show how you get PID for the contents in '/opt/apache/qwest/websites' directory.

Can you show what is in '/opt/apache/qwest/websites'

ls -l /opt/apache/qwest/websites/

drwxr-x--- 9 foss foss 4096 Apr 30 10:54 aa99036-eap-int1-30101-40086
drwxr-x--- 9 foss foss 4096 Dec 5 2013 somak-30135-40122
drwxr-x--- 9 foss foss 4096 Oct 17 2013 mlevens1-30133-40120
drwxr-x--- 9 foss foss 4096 Aug 4 07:52 mlevens-30099-40084
drwxr-x--- 9 foss foss 4096 Oct 6 2011 aqcb-40015


And also, show how you get PID for the contents in '/opt/apache/qwest/websites' directory.

/opt/apache/qwest/websites$ ps -ef | grep somak-30135-40122
foss 8963 1 0 00:59 ? 00:00:00 /bin/bash /opt/apache/qwest/websites/somak-30135-40122/watchdog httpd.worker -d /opt/apache/qwest/websites/somak-30135-40122 -DSSL
foss 8981 1 0 00:59 ? 00:00:00 httpd.worker -d /opt/apache/qwest/websites/somak-30135-40122 -DSSL
foss 8985 8981 0 00:59 ? 00:00:02 httpd.worker -d /opt/apache/qwest/websites/somak-30135-40122 -DSSL
foss 8991 8981 0 00:59 ? 00:00:01 httpd.worker -d /opt/apache/qwest/websites/somak-30135-40122 -DSSL
foss 30108 19811 0 08:59 pts/0 00:00:00 grep somak-30135-40122


In order to get the PID for this app, I am using the below command in the code :

ps -ef | grep somak-30135-40122|grep -v 'grep'|head -1|cut -d' ' -f7
8963


That is why i have included in the loop , to get the status of all the applications

apps=/opt/apache/qwest/websites
cd $apps
###### This will print list of all applications into one txt file######
ls > print.txt

for username in `awk -F: '{print $1}' /opt/apache/qwest/websites/print.txt`
do
echo "Username $((i++)) : $username"

those arent programs they are directories. maybe you can pgrep watchdog and then grep for the directory name in a loop but again... limited insite into what you are trying to achieve.

do you have any linux technicians onsite that can program this for you ?

Let me re-build my question, forget about the print.txt file, now from the below path:

ls -l /opt/apache/qwest/websites/

somak-30135-40122
mlevens1-30133-40120


FYI, These are the application directories where httpd resides,


Now, Can you help me of mofying/writing a script which will produce output of its process and sends an email to take an action on it, in order to start the httpd.worker process

this seems very site specific (meaning that every corporation have different methods and programs to monitor things -- even if they are all using linux).

can you provide the output of:

It will gives you the list of all the processes that are in the websites folder. The thing is all the apps are located on the same server, if it is on seperate machines i would have written a small if condition and set in cron on daily basis.