LinuxQuestions.org - [SOLVED] Find position of specific word in a line

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rajeshpvndd

11-05-2011 07:38 AM

Find position of specific word in a line

Hi
I have a line, aa bbb c dddd eeeee. How to read the position of the word "dddd", as "4" in bash. Please help.
Thanks

JSkywalker

11-05-2011 07:47 AM

Code:

echo "aa bbb c dddd eeeee" | awk -v t="dddd" '{ for (x=1; x<=NF; x++) { if ($x==t) { print "x=" x; exit(0) }} exit(-1);}'

catkin

11-05-2011 07:53 AM

Or a pure bash solution

Code:

#!/bin/bash

line='aa bbb c dddd eeeee'

word='dddd'

array=( $line )

for (( i=0; i<${#array[*]}; i++ ))

do

        [[ ${array[i]} = $word ]] && break

done

echo "$i"

The output is zero-based and it does not deal with the case where the word does not appear in the line.

rajeshpvndd

11-05-2011 07:57 AM

Thanks
It worked...

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