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Trying to write a short script that will tell me whether the permissions for 2 files, whose names are given as arguments to the script, are identical. If the permissions are the same, output the common permission field. If they are different, I need to output each file name followed by its permission field. I've been trying to use the cut command but seem to be missing something. Any suggestions would be appreciated. Thanks,
Click here to see the post LQ members have rated as the most helpful post in this thread.
This is kinda hacky but it's short and simple to understand and doesn't use many tools.
FILEP1=`ls -l $1 | cut -f1 -d' '`
FILEP2=`ls -l $2 | cut -f1 -d' '`
for i in `seq 1 10`; do
VAL1=`echo $FILEP1 | cut -c$i`
VAL2=`echo $FILEP2 | cut -c$i`
if [ $VAL1 == $VAL2 ]; then
echo "Bit $i is the same ($VAL1)";
echo "Bit $i is different ($VAL1 vs $VAL2)";
if [ $DIFF -gt 0 ]; then
echo "$FILEP1 $FILEN1"
echo "$FILEP2 $FILEN2"
Needs error checking and probably won't function with special characters as written.