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Old 12-23-2011, 01:56 AM   #1
pinga123
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Registered: Sep 2009
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Few queries regarding awk...


One of the command output is as below.

Code:
-rw-r--r--+ 1 root root 75G Nov 21 16:43 /var/ovs/mount/86BXXX/running_pool/Machine1/System-sda.img
-rw-r--r--+ 1 root root 75G Nov 21 16:36 /var/ovs/mount/86BXXX/running_pool/Machine2/System.img
-rw-r--r--+ 1 root root 150G Sep 23 19:13 /var/ovs/mount/86BXXX/running_pool/Machine3/System-hda.img
How would i filter it to get output like this.

Code:
Machine1 21 Nov
Machine2 21 Nov
Machine3 23 Sep
I m using awk but dont know how to deal with two delimiters i.e. space and /.

Last edited by pinga123; 12-23-2011 at 02:32 AM.
 
Old 12-23-2011, 02:41 AM   #2
sathish_s
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Registered: Aug 2011
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cat ss| awk -F/ '{print $1 $7}' |awk '{print $9" "$7" "$6}'
Machine1 21 Nov
Machine2 21 Nov
Machine3 23 Sep
[root@localhost Desktop]# cat ss
-rw-r--r--+ 1 root root 75G Nov 21 16:43 /var/ovs/mount/86BXXX/running_pool/Machine1/System-sda.img
-rw-r--r--+ 1 root root 75G Nov 21 16:36 /var/ovs/mount/86BXXX/running_pool/Machine2/System.img
-rw-r--r--+ 1 root root 150G Sep 23 19:13 /var/ovs/mount/86BXXX/running_pool/Machine3/System-hda.img
 
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