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There are some log files that I wish to get some information from (Apache Access Log) but it is HUGE! All I need as of right now is any information from date and time A to date and time B. What commands can I use to extract this information from the access_log and put it into another file with just that information? I created a file called "access_info" by doing
but I was not sure where to go from there. Thank you everyone in advance for your help!
You may want to adopt the practice of enclosing regular expressions in single quotes when invoking grep within bash. Bash uses some of the same meta-characters as used in regular expressions (even though they mean different things).
grep '2011-03-18' access_log
In this case it shouldn't matter, so frankbell's example should work fine. If your regular expression included [, *, or | then Bash would eat them before grep.
Telengard, becoming proficient at regular expressions is next on my list.
I began experimenting with Linux in 2005 to help with my Unix and programming classes. I've been using Linux on my own machines since 2006. In April 2009 I switch to Linux full time on my personal desktop. I still don't consider myself proficient with regular expressions. Take your time. ;D
A few tips you may find helpful:
man 7 regex provides a fairly easy to read overview of regular expressions.