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Old 08-11-2008, 06:27 AM   #1
hamimi
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Registered: Mar 2008
Location: Johannesburg
Posts: 5

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extracting field from line


Hi
I would like to extract a field from a log file,
eg: Backup|5.4.8 5.2.4|OK|Fri Aug 8 21:30:13 2008|172.29.12.50/489c9ec5|2|11|01:53:46|92975371081/92975371081/1177124864|00:17:08:5b:fa:54|gnslnx|Linux5.2.4

the only field i need is after the first /
i.e 489c9ec5
I tried this :
tail -1 /LOG|awk -F"/" '{print $2}'
but get all extra stuff as well:
489c9ec5|2|11|01:53:46|92975371081

Any Help will be apreciated

thanks
Hamim
 
Old 08-11-2008, 06:47 AM   #2
pixellany
LQ Veteran
 
Registered: Nov 2005
Location: Annapolis, MD
Distribution: Arch/XFCE
Posts: 17,802

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You specified "/" as the field separator, so you got everything between the first two instances of "/". So far, all is normal.

How about this?
Quote:
awk -F "|" '{print $2}' filename | sed 's?.*/??'
 
  


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