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I have Red Hat v9 installed on my main hard drive which is on IDE0 as the master. I would like to install winXP onto my secondary hard drive which is on IDE1 as the slave. Would I be able to dual boot normally? Could I boot winXP when I want and Red Hat when I want without incurring any serious mbr errors? Please help!!
this way the MBR on your main drive doesn't get touched, and if you feel like it you can safely remove winxp or redhat without affecting the other, if you remove redhat all you need to do is connect the winxp drive to primary master.
Yea each drive can have a mbr, xp will modify the mbr on the drive its on during installation, but only the drive that is set to the first bootable device is going to be used.
If you connect your winxp drive to primary master, or set in bios to boot from D: first it'll load winxp directly.
Thanks for all your help bro. And finally. So if I install WinXP to the secondary and leave that drive as the slave, then the Red Hat booter program will start when I boot the computer (assuming I leave the BIOS set to boot from the master hard drive), and the booter program will let me choose either Red Hat or WinXP to boot, right? And it'll do this without screwing up the MBRs for eachother... eh?
Your code didn't work. I entered it into grub.conf exactly as you typed it. But when the boot menu comes up, and I choose WinXP, it says "incorrect drive." Anyone know of working code?? Note: I have two hard drives. Linux is on the master, WinXP is on the slave.