[SOLVED] du style directory listing with file numbers
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Is there a command to return a recursive listing of sub-directories and the number of fils in them?
I have found plenty of ways to give me the total number of files in a directory structure, but none that gives a list of the sub-directories with the number of files in them. "du" gives me a listing of directories with their sizes, but I couldn't find an option (or any other way) to give me the number of files as well.
Ideally, I'd like to get list with "Size" "Files" "Dir name" - but I don't want to be greedy, just the last two would be a great help. And the order of the columns doesn't matter.
Is there a "simple" command line solution or do I need a shell script for that?
for r,d,f in os.walk( os.path.join(root,"path1","path2") ):
print "In directory: %s, there are %d files" %(r,len(f))
for files in f:
print "File: %s, size: %d bytes" %( os.path.join(r,files) , os.path.getsize(path ) )
Last edited by ghostdog74; 09-07-2010 at 12:00 AM.
Unfortunately, your snippet returned the following error.
./dirlist.py: line 3: syntax error near unexpected token `('
./dirlist.py: line 3: `for r,d,f in os.walk( os.path.join(root,"path1","path2") ):'
I copied your snippet into a file "dirlist.py",
then: chmod +x dirlist.py
followed by ./dirlist.py
Python has been on my "wish-to-learn" list for some time, but I don't know enough (or anything) of it to fix the problem. Hopefully, in the not too distant future, I will find the time to explore Python and understand what's gone wrong here.
Your "oneliner" worked a treat, just what the doctor ordered. I will try to pick it appart and see how the individual bits and pieces work together.