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disk quotas shell script

Hello.. I wrote the following shell script to run disk quotas for assigning limits to users. I need to know the partition which the user has created and mount it. So i copied the partitions (which will be displayed after running fdisk -l) and separted the last line from it and cut the required partition name from it. Then this should be passed to the next line (using mount). Here I am facing the problem.. It is returning the error "device not found", that means the variable "$part" is not giving the partition name..

The following is my code:

Code:

VSIZE=100m;



fdisk /dev/sda >/dev/null 2>&1 <<EOF

n

p

3



+${VSIZE}M

w

EOF



partprobe /dev/sda



fdisk -l > file1



awk 'NF{s=$0}END{print s}' file1 > file2



part=(`cut -c "1 2 3 4 5 6 7 8 9 10" file2`)



mkfs.ext3 $part



mkdir /var/likes



mount $part /var/likes



chmod 777 /var/likes



quotacheck -cugv /var/likes



quotaon $part



setquota -u kal 2 3 4 5 -a $part

I'd advise you to put a

Quote:

echo "$part"

line in the script to see what it is actually returning.The you can fix from there.

Thanks for ur reply.I tried it,it is printing required value ( partition name) itself.But its not working in mount statement

I mean echo $part to see what is actually being printed after the

Quote:

part=(`cut -c "1 2 3 4 5 6 7 8 9 10" file2`)

This command doesnt seem to be working....I thing it should be

Quote:

cat file2 | cut

depending on what you wanna do..

Try

Code:

set -xv

as the first line :)

@cbtshare
even this

Quote:

cat file2 | cut

is also not working fine :(

@Chris
what is meant by

Quote:

set -xv

Try it & see ;)

Basically its a form of debugging; it shows you the before and after version (inc results) of parsing each line.
A key tool for fixing shell scripts.

http://tldp.org/LDP/Bash-Beginners-G...tml/index.html
http://www.tldp.org/LDP/abs/html/

@chris
Thank you.. Ya it's debugging.. but what is the solution to solve the problem in code??