Dear all,

I have a file "c" that has all the task that are scheduled.
for ex the content of c file is

10 4 2 30 * sh run.sh
11 20 2 7 * sh inc.sh
19 22 9 11 * sh inc.sh


now i need to delete only second task.If i use crontab -r it deletes all tasks.and if i remove that from the file c ,then also after running crontab -l ,i am getting all 3 tasks schedule.

Can anyone guide me to solve this issue.

With regards,
Deepti.

do you have a reference to the file C in your crontab that executes file C? If so I dont see why you can't just remove the lines from file C, if thats the case there is no need to do anything with crontab.


example
crontab -l
_________________________________
00 11 11 06 * /path/to/file/c
__________________________________


ls C
__________________________________

10 4 2 30 * sh run.sh
11 20 2 7 * sh inc.sh
19 22 9 11 * sh inc.sh
__________________________________



Now that I think about it.. If that IS the content of file C why do you have crontab date structure?





If this is in your crontab

10 4 2 30 * sh run.sh
11 20 2 7 * sh inc.sh
19 22 9 11 * sh inc.sh


then just do a
crontab -e

dd on the line you want to remove and save the crontab, edit it just like you would any vi file..



Or am I completely misreading your post....