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Old 07-11-2014, 02:07 AM   #1
hoi
LQ Newbie
 
Registered: Jun 2013
Posts: 29

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decoration of data file


I have a file like:
1 17 0.866
1 18 0.866
1 19 0.866
1 21 0.866
2 17 0.866
2 18 0.866
2 20 0.866
2 22 0.866
3 17 0.866
3 19 0.866
3 23 0.866
3 26 0.866
1 10 1.000
1 11 1.000
2 11 1.000
2 12 1.000
3 15 1.000
3 16 1.000


I want to modify the above file with respect to column three, into two files.
file1:
1 17 18 19 21
2 17 18 20 22
3 20 19 23 26

file2:
1 10 11
2 11 12
3 15 16
 
Old 07-11-2014, 09:45 AM   #2
kaushalpatel1982
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Registered: Aug 2007
Location: INDIA
Distribution: CentOS, RHEL, Fedora, Debian, Ubuntu, LinuxMint, PCLinuxOS
Posts: 153

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There is problem in FILE1 line 3, Output should be :

"3 17 19 23 26" instead of "3 20 19 23 26"


Code:
#!/bin/bash
j=3

i=1
while [ $i -le $j ]
do
	values=`cat file | grep 0.866 | awk '{ print $1, $2 }'| grep ^$i | cut -d" " -f2 | xargs -n 5`
	echo $i $values >> file1
	i=`expr $i + 1`
done

i=1
while [ $i -le $j ]
do      
        values=`cat file | grep 1.000 | awk '{ print $1, $2 }'| grep ^$i | cut -d" " -f2 | xargs -n 5`
        echo $i $values >> file2
	i=`expr $i + 1`
done

Last edited by kaushalpatel1982; 07-11-2014 at 09:48 AM.
 
2 members found this post helpful.
Old 07-12-2014, 02:08 AM   #3
hoi
LQ Newbie
 
Registered: Jun 2013
Posts: 29

Original Poster
Rep: Reputation: Disabled
Quote:
Originally Posted by kaushalpatel1982 View Post
There is problem in FILE1 line 3, Output should be :

"3 17 19 23 26" instead of "3 20 19 23 26"


Code:
#!/bin/bash
j=3

i=1
while [ $i -le $j ]
do
	values=`cat file | grep 0.866 | awk '{ print $1, $2 }'| grep ^$i | cut -d" " -f2 | xargs -n 5`
	echo $i $values >> file1
	i=`expr $i + 1`
done

i=1
while [ $i -le $j ]
do      
        values=`cat file | grep 1.000 | awk '{ print $1, $2 }'| grep ^$i | cut -d" " -f2 | xargs -n 5`
        echo $i $values >> file2
	i=`expr $i + 1`
done
Thank you Kaushal....
 
  


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bash scripting, c programming, cprogramming, shell script


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