Hi All,

I am new to this Site. My task would be to suppress the hours, minutes, seconds from date which is in epoch format and the value is dynamical.

Below are my steps i have tried and i am getting different results.

For example I have used ‘20160101 01:04:01’ value and converted into epoch time.
[ ~]$ date -d "20160101 01:04:01" +%s
1451628241
I have calculated the number of days from the epoch time using the below math
[~]$ echo "1451628241/86400"|bc
16801
Then, I have multiplied with 86400 with the results.
[~]$ echo "16801*86400"|bc
1451606400
I have converted the epoch time and I would expect the output as ‘20160101 00:00:00’.But I am getting the bellow output.
[~]$ date -d @1451606400 "+%Y%m%d %H:%M:%S"
20151231 19:00:00

Please advice.

What's wrong with just using
to return just the parts you need?

1 members found this post helpful.

You need to watch time zones. Epoch is in UTC, when you convert to an integer multiple of 86400 you're converting to 00:00 UT, and apparently the local time offset where you live is -5 hours. Add the "-u" flag in your last command to print out that epoch time in UTC and you'll see it's what you expect.

2 members found this post helpful.

Thank you TenTenths. I have read through the "How To Ask A Question" link and i understand the points listed. I will make sure that i will follow the instructions in future.(I would like to understand the actual output if the results with the seconds thats is the reason i haven't tried '"+%Y%m%d"' format)

Thank you suicidaleggroll. It works for me.

what about leap seconds

What about them?
Leap seconds only need to be taken into account the day surrounding their occurrence or when converting to/from GPS time.