you may be able to accomplish this with 'dd'.
myfile.tar == 688MB
to break it, first part 400MB, second part remaining (288MB)
Code:
dd if=myfile.tar of=myfile.tar.dd.1 bs=4096 count=102400
dd if=myfile.tar of=myfile.tar.dd.2 bs=4096 skip=102400
then to construct the single .tar again
Code:
dd if=myfile.tar.dd.2 of=myfile.tar.dd.1 bs=4096 seek=102400
mv myfile.tar.dd.1 myfile-from-dd.tar
it'd be a good idea to have a SUM for the original (md5sum, sha1sum, ...) to make sure it matches after you put the parts back together.
in my example (and test) it did
Code:
sha1sum myfile.tar myfile-from-dd.tar
da6c69be653d619080566808d43eddff89185c6c myfile.tar
da6c69be653d619080566808d43eddff89185c6c myfile-from-dd.tar
and the files extracted successfully with 'tar xvf myfile-from-dd.tar' and their sums matched as well (as expected since the tar files were identical but just an extra level of checking
)
you can look at the man page for more options and see what is happening but i think it may be do-able like this. You'll just want to take care not to lose or forget the values you used or it could get ugly...
also, for bs= i used the filesystem block-size as reported by dumpe2fs for the partition i was working with the files on; not sure if it will actually matter or not but was used for consistency.
hope this helps.