Cut the third colum

ust · 06-03-2009, 01:43 AM

The below is the result of command "ls" ,

-rw------- 1 user1 sys 4983 Jun 3 14:25 ora_log1

can advise if I want to have a command ( script ) that cut the third colum of the line , what can i do ? Thx

* my expected outoput is "user1" .

druuna · 06-03-2009, 01:47 AM

Hi,

What you show is not the output of ls, but ls -l.

Anyway, if you want the third column from the output you show:

ls -l | awk '{ print $3 }'

Hope this helps.

PS: You might want to take a look at the ls manpage, maybe it has an option to only show the username.....

noctilucent · 06-03-2009, 02:06 AM

Hello.

Quote:

Originally Posted by ust

<..> I want to have a command ( script ) that cut <..>

Also make sure to check out the command called "cut" :-)

colucix · 06-03-2009, 02:43 AM

Information about files are provided by the stat command. too:

Code:

owner=$(stat -c%G $file)

kunalghosh · 06-03-2009, 03:03 AM

the following command will cut and give the 3rd column for you.

ls -l | cut -d " " -f 4

in case this doesnt work try playing around with -f N changing N to 3 should do the trick. read the man page for cut -- "man cut" to get a description of what was done in the code.

regards

Hobbletoe · 06-03-2009, 07:30 AM

Because ls uses tabs to format the output better in some places, you can't use just a space as a delimiter. What I usually do is pass the info through tr first, replacing all of the white space with a single space, and then do the cut.

Code:

ls -l | tr -s '[:blank:]' ' ' | cut -d' ' -f3