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The section 5 of the manual provides information about the crontab's syntax:
man 5 crontab
Anyway it will suggest how to run a cron job every sunday. Then you have to add an extra check for the day of the month, that has to be ≥ 15 and ≤ 21. You can add a conditional expression in the crontab entry itself or at the beginning of the script.
Last edited by colucix; 01-09-2011 at 12:50 PM.
Reason: Added extra information
Nope. This will not work as intended. The two day fields (day of the month and day of the week) in a crontab entry add up: this means the suggested line will run every day between 15th and 21st plus every sunday. The man page (section 5) of crontab clearly states that. This is why I suggested an explicit check for the day of the month in my previous post.
Last edited by colucix; 01-09-2011 at 04:17 PM.
Reason: spelling corrected
Taking a solution from another forum does not necessarily mean it's correct even if they claim it works. Anyway, as clearly stated by the crontab man page:
Note: The day of a command's execution can be specified by two fields — day of month, and day of week. If both fields are restricted (ie, aren't *), the command will be run when either field matches the current time. For example, ``30 4 1,15 * 5'' would cause a command to be run at 4:30 am on the 1st and 15th of each month, plus every Friday.
You can easily try that. Suppose now is 08:00 AM on January, 11st (Tuesday). You can set a cron job like this:
5 8 15-21 * 2 date >> $HOME/cron.log
and see if it runs. Practice is more helpful than theory!
You could at least show some effort and post what you've tried so far. Have you read the suggested documentation? Have you understood advices in post #6? Have you followed the further discussion? What are your shell scripting skills?