Hi,

I have created a shell script which searches users home directories based on their group membership and copies a file if it exists to my home directory. I would also like to create a logfile of all the users that do not have the file.
I am a newbie and there is probably a simple solution but I have been unable to find one.

Do you think you could share what you have so far?

awk -F : '$4 =501{print$1}' /etc/passwd | while
read user
do

find /home/*/pickup -iname 'pickup' | xargs -i cp "{}" /home/gd121462/collection

done

Anybody got ideas they want to share with me to help resolve my problem. The code that I have so far is it OK? It seems to do what I want except I do not know how to create the logfile with the users names with no file to pick up.

Something like that should work. If the previous command fails, it will put the user in a the file.

Hi O.o,

I have tried using the code for creating the log file substituting the path for the logfile etc and am getting the following error
./testcode: [0: command not found
The files still get copied to the pickup folder though.
If I amend the code with the following

awk -F : '$4 =501{print$1}' /etc/passwd | while
read user
do

find /home/*/pickup -iname 'pickup' | xargs -i cp "{}" /home/gd121462/collection

if [ $? -ne 0 ];
then
echo $user > /some/log/file
fi | (date;echo $user) | xargs >> log
done

I do get a log file but it gives me every user on the system rather then the ones who belong to the group and have no file in the pickup folder