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Old 06-02-2011, 03:58 AM   #1
kpinto
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Registered: Jun 2011
Posts: 3

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Smile count how many number occurrences in series


hi all ;
i try to make a script in bash that u choose a number
for example 501 and another number like 1
and find how much the 1 number repeat in all numbers from 1 to 501
for example 11 -->1 repeat 2 times.

in 1 to 501 the number 1 repeat 200 times

THX
 
Old 06-02-2011, 04:16 AM   #2
arochester
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This looks very hypothetical and like homework.

I cannot think of a reasonable, practical use for such an operation.

What have you written of the script so far and what result does it produce?
 
Old 06-02-2011, 05:00 AM   #3
kpinto
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Registered: Jun 2011
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i am not a student but it's a question that my child receive in mat he answer on this question and i try to figure how to wrote a bash script.

i made this script to write all number from 1 to 501

#!/bin/bash
COUNTER=501
until [ $COUNTER -lt 1 ]; do
echo $COUNTER
let COUNTER-=1
done


and made this script to find the number 1
awk '/1/ { count++ } END { print count }' /debug/file.txt

but i receive 177 and i don't know how he can count digits in number.

thanks for you're answer.
 
Old 06-02-2011, 08:24 AM   #4
grail
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Well I actually get 201 when going up to 501 ... havent checked by hand but the lower values test and work properly:
Code:
awk -vlast=501 -vsearch="1" 'BEGIN{for(i=1;i<=last;i++)n += split(i,_,search) - 1;print n}'
 
Old 06-02-2011, 09:22 AM   #5
kpinto
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Registered: Jun 2011
Posts: 3

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many thx

i will try to figure out what u did
it works properly
 
  


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