convertion of seconds to date and time in linux shell script
 

Hi,

I am looking for command or function to convert seconds to date.

In shell script i will get seconds into one varible, I need to convert seconds to date and append to file(Ex: filename.<date-time-format>)

I.e
ts=1280353895 -->This is date and time in seconds.This needs to convert
YYYYMMDDHHMMSS format.

Through date command with options i can get this format.

#date +%Y%m%d%H%M%S ; date +%s; date
20100813061446 --->YYYYMMDDHHMMSS format.(I am looking this format)
1281705286 ----> time in seconds(getting into variable.need to convert)
Fri Aug 13 06:14:46 PDT 2010---->date


Can any one help to get this format?

Thanks in advance.

Hi,

Are you looking for this: date -d @$ts
Or formatted differently: date -d @$ts +"%d-%m-%Y %T %z"

Hope this helps.

Try this

druuna you beat me :)


@ OP

as your require format you can use

regards,

Hi sem/druuna,

Thanks for your immediate response to my query.

I got the required format and i used following command.

date -d "1970-01-01 $ts sec" +"%Y%m%d%H%M%S" [ts=1280353895]

O/P:20100728225135 [YYYYMMDDHHMMSS]

Thanks
Naveen

Hi,

Nice to see you got a working solution!

The 1970-01-01 part is not needed. This date is a standard default on unix/linux systems. You do not need to mention it in your command.

This will do the same as the one you posted: date -d @$ts +"%Y%m%d%H%M%S"

BTW: You're welcome :)

Druuna,

you are correct The 1970-01-01 part is default linux/unix system time.

with date -d @$ts +"%Y%m%d%H%M%S" this command i am getting following message
date: invalid date `@1280353895'

In my script i am assigning this format to one variable(DATE=`date -d @$ts +"%Y%m%d%H%M%S"`) and using this "DATE" in different places.

But if i use the epoch time (DATE=`date -d "1970-01-01 $ts sec" +"%Y%m%d%H%M%S"`) i am getting the the required format.

Please correct me if i am wrong.

Hi,

To put the output of a command into a variable you need to do the following:

DATE=$(date -d @$ts +"%Y%m%d%H%M%S")
or
DATE=`date -d @$ts +"%Y%m%d%H%M%S"` -> those are back ticks.

Now you can use $DATE.

Hope this helps.

Maybe you're using an old version of date or something that's not compliant to default linux/unix system time.

Hi,

I have to agree with konsolebox on this issue.

What does date --version tell you?

Hope this helps.

Hi druuna,
Following is the date version.

#date --version
date (coreutils) 5.2.1
Written by David MacKenzie.

Copyright (C) 2004 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.


with following commands i am getting date: invalid date `@1280353895'
DATE=$(date -d @$ts +"%Y%m%d%H%M%S")
or
DATE=`date -d @$ts +"%Y%m%d%H%M%S"`

I am not sure why you are using @$ts?If i am not wrong $ts is enough.

But its working fine with following command
DATE=`date -d "1970-01-01 $ts sec" +"%Y%m%d%H%M%S"`


Thanks
Naveen

Hi,

Your date version is a bit old and that could be the problem.

I have to use the @ in order to make it work (tried with the oldest date version I could find):
As you can see the last command (date -d "1970-01-01 $ts sec" +"%Y%m%d%H%M%S") also works. I guess you need to use that one in your case.

Hope this helps.

Thanks a lot druuna.

I am using date -d "1970-01-01 $ts sec" +"%Y%m%d%H%M%S" in my script.

Thanks
Naveen

You're welcome :)