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Old 10-24-2005, 09:14 PM   #1
tsilok
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Registered: Sep 2005
Posts: 6

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Question Converting number to locale's abbreviated month name


Is there any command to convert an integer (1-12) to (Jan-Dec)?
E.g. I pass in input parameter 3, it will return "Mar"

Thx,
Tsi Lok
 
Old 10-25-2005, 01:12 AM   #2
AwesomeMachine
Senior Member
 
Registered: Jan 2005
Location: USA and Italy
Distribution: Debian jessie/sid; OpenSuSE; Fedora
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I'll write on for you.

#!/bin/bash
##filename calendar
##converts integers 1-12 to Gregorian calendar month names

if echo "$1" | grep '12'
then
echo "December"
exit 0
fi
if echo "$1" | grep '11'
then
echo "November"
exit 0
fi
if echo "$1" | grep '10'
then
echo "October"
exit 0
fi
if echo "$1" | grep '9'
then
echo "September"
exit 0
fi
if echo "$1" | grep '8'
then
echo "August"
exit 0
fi
if echo "$1" | grep '7'
then
echo "July"
exit 0
fi
if echo "$1" | grep '6'
then
echo "June"
exit 0
fi
if echo "$1" | grep '5'
then
echo "May"
exit 0
fi
if echo "$1" | grep '4'
then
echo "April"
exit 0
fi
if echo "$1" | grep '3'
then
echo "March"
exit 0
fi
if echo "$1" | grep '2'
then
echo "February"
exit 0
fi
if echo "$1" | grep '1'
then
echo "January"
exit 0
fi
echo "This program outputs month names for integer inputs between 1 and 12. Please make adjustments as necessary"
exit 1

Copy and paste this to a file named calendar.
do
chmod a+rx calendar
mv calendar /usr/local/bin

to run the program:

romulus4:/home/sam# calendar 12
 
Old 10-25-2005, 11:53 AM   #3
jdiemer
LQ Newbie
 
Registered: Aug 2004
Distribution: Redhat Enterprise
Posts: 15

Rep: Reputation: 0
This shell script uses the date command to ouput the locale's abbreviated month name, when you give the argument as a number (1-12) to the command line

#!/bin/bash
date -d "01-$1-01" +%b
 
Old 10-25-2005, 04:53 PM   #4
archtoad6
Senior Member
 
Registered: Oct 2004
Location: Houston, TX (usa)
Distribution: MEPIS, Debian, Knoppix,
Posts: 4,727
Blog Entries: 15

Rep: Reputation: 230Reputation: 230Reputation: 230
I assume from your title that you would like it to be locale independent. Since the man page for date says it works in the locale, it is just the thing to use; not to mention a case statement:
Code:
#! /bin/bash
#0 month.sh === print locale month abbr. from number
#@ by f.a.archibald.iii 	all rights reserved

_usage () {
cat << end_usage

month.sh    print locale month abbr. from month number
    Syntax:   month.sh <number_of_month>
    
end_usage
}

case $1 in 
  [1-9]|1[0-2])		date -d "$1/01" +%b	;;
  *)			_usage ;  exit 1
esac
And here is some test code:
Code:
chmod 755 month.sh

for ((x=0;$x<14;x++)) do 
   echo -ne "$x\t"
   ./month.sh $x
   echo -e "\033[A\t\t exit code is  $?" 
done
EDIT: Drat, jdiemer posted while I was composing & testing.
The core command is the same, though.

Last edited by archtoad6; 10-25-2005 at 04:59 PM.
 
Old 10-25-2005, 05:18 PM   #5
archtoad6
Senior Member
 
Registered: Oct 2004
Location: Houston, TX (usa)
Distribution: MEPIS, Debian, Knoppix,
Posts: 4,727
Blog Entries: 15

Rep: Reputation: 230Reputation: 230Reputation: 230
If you want to have some fun w/ locales, run:
Code:
set |  grep ^LC
& record your current locale; then run any or all of the following (followed by my test code above):
Code:
LC_ALL=de_DE
LC_ALL=fr_FR
LC_ALL=pt_BR
LC_ALL=en_US
Or any others you have installed. Just be sure to restore your own when you are done.
 
  


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